“Python Converter to C.” Kod odpowiedzi

Python Converter to C.


 float(input("Digite quantos litros você quer abastecer: "))
 input("Digite A para álcool ou G para gasolina: ")

if combustivel == "A" or combustivel == "a":
    preco = litros * 1.9
    if litros <= 20:
        preco -= 1.9 * litros * 3 / 100
    else:
        preco -= 1.9 * litros * 5 / 100
elif combustivel == "G" or combustivel == "g":
    preco = litros * 2.5
    if litros <= 20:
        preco -= 2.5 * litros * 4 / 100
    else:
        preco -= 2.5 * litros * 6 / 100
print(f"O preço a pagar é R${preco:.2f}")
Comfortable Cat

Python Converter to C.

importb (ptint)
Lovely Lyrebird

Python Converter to C.

s=input()

x= int(input())

unt = 0

n = 0

1=len(s)

f= False

for i in range(1) : n=n*10+int (s[i])

if n<=x:

print (n)

f=True

else:

if f:

count += 1 n=int(s[i]) f= False

if n<=x:

f = 7 True

else:

n = 0

if f= True: count +=1

print(count)
Old-fashioned Oryx

Python Converter to C.

int x 2;

2 x = x <<< 1;
Jettiboina Srinivasa Rao

Python Converter to C.

max1 = -1
Thoughtless Tern

Python Converter to C.

void(){
	int a = 1;
    int b = 4;
    
    int c = a+b;
    return;
    }
Terrible Tuatara

Python Converter to C.

def fitness(cand):
    candidato=[]   
    for ia in range (75):
        soma1=0
        soma2=0
        soma3=0
        ib=cand*12 #endereço do individuo dentro da matriz B
        for j in range (nv): 
            soma1 = out[ia][ib+j] + soma1 #soma elementos do cluster 1
            soma2 = out[ia][ib+j+nv] + soma2 #soma elementos do cluster 2
            soma3 = out[ia][ib+nv*2] + soma3 #soma elementos do cluster 3
                        
        candidato.append(min(np.sqrt(soma1),np.sqrt(soma2),np.sqrt(soma3)))
        
    return np.sum(candidato)
Terrible Tuatara

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