wracać
#include <iostream>
using namespace std;
int n, kq[11], dd[10];
void xuat()
{
for (int j=1; j<=n; j++)
cout<< kq[j]<<" ";
cout << endl;
}
void backtrack(int i)
{
if (i>n) xuat();
for (int j=1; j<=n; j++)
if (dd[j]==0)
{
dd[j]=1;
kq[i]=j;
backtrack(i+1);
dd[j]=0;
}
}
int main()
{
cin >> n;
for (int i=1; i<=9; i++)
dd[i]=0;
backtrack(1);
}
Yucky Yak