“Wyjście debugowania do konsoli i dziennika” Kod odpowiedzi

Wyjście debugowania do konsoli i dziennika

public static class Logger
{
    public static StringBuilder LogString = new StringBuilder();
    public static void WriteLine(string str)
    {
        Console.WriteLine(str);
        LogString.Append(str).Append(Environment.NewLine);
    }
    public static void Write(string str)
    {
        Console.Write(str);
        LogString.Append(str);

    }
    public static void SaveLog(bool Append = false, string Path = "./Log.txt")
    {
        if (LogString != null && LogString.Length > 0)
        {
            if (Append)
            {
                using (StreamWriter file = System.IO.File.AppendText(Path))
                {
                    file.Write(LogString.ToString());
                    file.Close();
                    file.Dispose();
                }
            }
            else
            {
                using (System.IO.StreamWriter file = new System.IO.StreamWriter(Path))
                {
                    file.Write(LogString.ToString());
                    file.Close();
                    file.Dispose();
                }
            }               
        }
    }
}