var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82reduce function sample solution[1,2,3,4,5].reduce((acc, current)=>acc+current, 0)function reduce(array, combine, start) {
let current = start;
for (let element of array) {
current = combine(current, element);
}
return current;
}
console.log(reduce([1, 2, 3, 4], (a, b) => a + b, 0));
// → 10arr.reduce(callback( accumulator, currentValue[, index[, array]] )[, initialValue])
The reduce() method executes a reducer function (that you provide) on each element of the array, resulting in single output value.
The reducer function takes four arguments:
Accumulator (acc)
Current Value (cur)
Current Index (idx)
Source Array (src)
//syntax
arr.reduce(callback( accumulator, currentValue, [, index[, array]] )[, initialValue])
//example flatten an array
let flattened = [[0, 1], [2, 3], [4, 5]].reduce(
( accumulator, currentValue ) => accumulator.concat(currentValue),
[]
)