“? W JavaScript” Kod odpowiedzi

... w JavaScript

// The `...` operator breaks down an array to individual arguments.
// For example lets create an array,
let array = [1, 2, 3];

// And a function that will return a sum of 3 values.
function sum(x, y, z) {
	return(x + y + z);
}

// The `sum` function doesn't accept an array as a single argument,
// so a solution for this would be calling it individual indexes in the array:
sum(array[0], array[1], array[2]);

// Or we can just do:
sum(...array)
// does the same thing
Sheeeev66

Co jest ... w JavaScript

function sum(...numbers) {
	return numbers.reduce((accumulator, current) => {
		return accumulator += current;
	});
};
 
sum(1,2) // 3
sum(1,2,3,4,5) // 15
Brainy Butterfly

Co to jest $ w JavaScript


//----------------------------------------
//Question:What is ${variable_name} in javascript?
//----------------------------------------
//You can insert variables in a string (If you write string in backtick)
//Example
const username = "Omar";
//This will Work!
console.log(`The username is ${username}`)//The username is Omar
//These wont Work!
console.log("The username is ${username}")//The username is ${username}
console.log('The username is ${username}')//The username is ${username}
Unreal Person

? W JavaScript

The optional chaining operator (?.) enables you to read the value of a
property located deep within a chain of connected objects without having
to check that each reference in the chain is valid.
correctYourPosture

... w JavaScript

let array = [...value]
Ugly Unicorn

~~ w JavaScript

~N = -(N+1)
Brainy Butterfly

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