“numer JavaScript do słów” Kod odpowiedzi

numer JavaScript do słów

var num = "zero one two three four five six seven eight nine ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen".split(" ");
var tens = "twenty thirty forty fifty sixty seventy eighty ninety".split(" ");

function number2words(n){
    if (n < 20) return num[n];
    var digit = n%10;
    if (n < 100) return tens[~~(n/10)-2] + (digit? "-" + num[digit]: "");
    if (n < 1000) return num[~~(n/100)] +" hundred" + (n%100 == 0? "": " and " + number2words(n%100));
    return number2words(~~(n/1000)) + " thousand" + (n%1000 != 0? " " + number2words(n%1000): "");
}
Darker

numer do słowa js

let a = [
  "",
  "one ",
  "two ",
  "three ",
  "four ",
  "five ",
  "six ",
  "seven ",
  "eight ",
  "nine ",
  "ten ",
  "eleven ",
  "twelve ",
  "thirteen ",
  "fourteen ",
  "fifteen ",
  "sixteen ",
  "seventeen ",
  "eighteen ",
  "nineteen ",
];
let b = [
  "",
  "",
  "twenty",
  "thirty",
  "forty",
  "fifty",
  "sixty",
  "seventy",
  "eighty",
  "ninety",
];

function inWords(num) {
  if ((num = num.toString()).length > 9) return "overflow";
  let n = ("000000000" + num)
    .substr(-9)
    .match(/^(\d{2})(\d{2})(\d{2})(\d{1})(\d{2})$/);
  if (!n) return;
  var str = "";
  str +=
    n[1] != 0
      ? (a[Number(n[1])] || b[n[1][0]] + " " + a[n[1][1]]) + "crore "
      : "";
  str +=
    n[2] != 0
      ? (a[Number(n[2])] || b[n[2][0]] + " " + a[n[2][1]]) + "lakh "
      : "";
  str +=
    n[3] != 0
      ? (a[Number(n[3])] || b[n[3][0]] + " " + a[n[3][1]]) + "thousand "
      : "";
  str +=
    n[4] != 0
      ? (a[Number(n[4])] || b[n[4][0]] + " " + a[n[4][1]]) + "hundred "
      : "";
  str +=
    n[5] != 0
      ? (str != "" ? "and " : "") +
        (a[Number(n[5])] || b[n[5][0]] + " " + a[n[5][1]]) +
        "only "
      : "";
  return str;
}

/* eslint eqeqeq: 0 */
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