pętla przez async JavaScript -4
const j = 10;
for (let i = 0; i < j; i++) {
asynchronousProcess(function() {
console.log(i);
});
}
Inquisitive Ibex
const j = 10;
for (let i = 0; i < j; i++) {
asynchronousProcess(function() {
console.log(i);
});
}