// Use to remove duplicate elements from the array
const numbers = [2,3,4,4,2,3,3,4,4,5,5,6,6,7,5,32,3,4,5]
//spreading numbers of the object into an array using the new operator
console.log([...new Set(numbers)])
// [2, 3, 4, 5, 6, 7, 32]let mySet = new Set()
mySet.add(1) // Set [ 1 ]
mySet.add(5) // Set [ 1, 5 ]
mySet.add(5) // Set [ 1, 5 ]
mySet.add('some text') // Set [ 1, 5, 'some text' ]
let o = {a: 1, b: 2}
mySet.add(o)
mySet.add({a: 1, b: 2}) // o is referencing a different object, so this is okay
mySet.has(1) // true
mySet.has(3) // false, since 3 has not been added to the set
mySet.has(5) // true
mySet.has(Math.sqrt(25)) // true
mySet.has('Some Text'.toLowerCase()) // true
mySet.has(o) // true
mySet.size // 5
mySet.delete(5) // removes 5 from the set
mySet.has(5) // false, 5 has been removed
mySet.size // 4, since we just removed one value
console.log(mySet)
// logs Set(4) [ 1, "some text", {…}, {…} ] in Firefox
// logs Set(4) { 1, "some text", {…}, {…} } in Chrome
const mySet1 = new Set()
mySet1.add(1) // Set [ 1 ]
mySet1.add(5) // Set [ 1, 5 ]
mySet1.add(5) // Set [ 1, 5 ]
mySet1.add('some text') // Set [ 1, 5, 'some text' ]
const o = {a: 1, b: 2}
mySet1.add(o)
mySet1.add({a: 1, b: 2}) // o is referencing a different object, so this is okay
mySet1.has(1) // true
mySet1.has(3) // false, since 3 has not been added to the set
mySet1.has(5) // true
mySet1.has(Math.sqrt(25)) // true
mySet1.has('Some Text'.toLowerCase()) // true
mySet1.has(o) // true
mySet1.size // 5
mySet1.delete(5) // removes 5 from the set
mySet1.has(5) // false, 5 has been removed
mySet1.size // 4, since we just removed one value
console.log(mySet1)
// logs Set(4) [ 1, "some text", {…}, {…} ] in Firefox
// logs Set(4) { 1, "some text", {…}, {…} } in Chrome