// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });
// For arrays with relatively few elements you can use apply:
const max = Math.max.apply(null, arr);
// or spread operator:
const max = Math.max(...arr);
const dates = [];
dates.push(new Date('2011/06/25'));
dates.push(new Date('2011/06/26'));
dates.push(new Date('2011/06/27'));
dates.push(new Date('2011/06/28'));
const maxDate = new Date(Math.max.apply(null, dates));
const minDate = new Date(Math.min.apply(null, dates));//get min/max value of arrays
function getArrayMax(array){
return Math.max.apply(null, array);
}
function getArrayMin(array){
return Math.min.apply(null, array);
}
var ages=[11, 54, 32, 92];
var maxAge=getArrayMax(ages); //92
var minAge=getArrayMin(ages); //11var values = [3, 5, 6, 1, 4];
var max_value = Math.max(...values); //6
var min_value = Math.min(...values); //1var numbers = [1, 2, 3, 4];
Math.max(...numbers) // 4
Math.min(...numbers) // 1function minMax(arr) {
return [Math.min(...arr), Math.max(...arr)];
}