“Discord Pycord Dodaj przycisk URL w widoku podklasowym” Kod odpowiedzi

Discord Pycord Dodaj przycisk URL w widoku podklasowym

class helpView(View):
  def __init__(self):
    super().__init__(timeout=None)

    supportServerButton = discord.ui.Button(label='Support Server', style=discord.ButtonStyle.gray, url='https://discord.com')
    self.add_item(supportServerButton)

  @discord.ui.button(label='Commands', style=discord.ButtonStyle.green)
  async def command_callback(self, button, interaction):
    await interaction.response.edit_message(embed=commandEmbed, view=commandView())