d = {"A":3, "B":1, "C":100}
# find key with lowest value
best_key = min(d, key=d.get)
print(best_key)
# output: B# Basic syntax:
key_with_max_value = max(dictionary, key=dictionary.get)
# Note, to get the max value itself, you can do either of the following:
max_value = dictionary[max(dictionary, key=dictionary.get)]
max_value = max(dictionary.values())
# Example usage:
dictionary = {"a": 1, "b": 2, "c": 3}
max(dictionary, key=dictionary.get)
--> 'c'# Works also with multiple equal minimum values
res = list(filter(lambda x: d[x]==minval, d))