Jak sprawdzić, czy liczba jest idealnym kwadratowym pythonem
import math
# Taking the input from user
number = int(input("Enter the Number"))
root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
print(number, "is a perfect square")
else:
print(number, "is not a perfect square")
Cute Capybara