Policz znaki w Pythonie String
>>> sentence = 'Mary had a little lamb'
>>> sentence.count('a')
4
Cheerful Cormorant
>>> sentence = 'Mary had a little lamb'
>>> sentence.count('a')
4
# Basic syntax:
import re
len(re.findall('[characters]', your_string))
# Example usage:
# say you want to count all G, g, C, or c characters in the following DNA seq
len(re.findall('[GgCc]', "ACGTGCAcgattcgatCGCTAGCTAG"))
--> 14#using dict comprehensions
sentence = "This is a long sentence that I have just written up for an example!"
dicto = {char: sentence.count(char) for char in set(sentence)}
print(dicto)#This returns a dictionary with the letter and amount of times it shows up in your sentence
#output: {'f': 1, 'u': 2, 't': 6, 's': 4, 'j': 1, 'o': 2, 'I': 1, 'r': 2, 'p': 2, 'w': 1, '!': 1, 'l': 2, 'n': 5, 'g': 1, 'T': 1, 'a': 5, 'h': 3, 'i': 3, 'v': 1, 'm': 1, 'e': 7, 'c': 1, ' ': 13, 'x': 1}
#sorted low to high:
print({k: v for k, v in sorted(dicto.items(), key=lambda item: item[1])})
#{'g': 1, 'x': 1, 'j': 1, 'f': 1, '!': 1, 'T': 1, 'w': 1, 'v': 1, 'I': 1, 'm': 1, 'c': 1, 'o': 2, 'u': 2, 'r': 2, 'l': 2, 'p': 2, 'i': 3, 'h': 3, 's': 4, 'n': 5, 'a': 5, 't': 6, 'e': 7, ' ': 13}# count the number of characters in a string:
len("The quick brown fox jumps over the lazy dog")
# OUTPUT: 43
# count the number of character OCCURENCES in a string:
string = "The quick brown fox jumps over the lazy dog"
string.count(" ")
# OUTPUT: 8