“Usuń element z listy, jeśli istnieje Python” Kod odpowiedzi

Usuń element z listy, jeśli istnieje Python

# 1) Almost-English style:
if thing in some_list:
	some_list.remove(thing)
    
# 2) Duck type, EAFP style:
with suppress(ValueError, AttributeError):
    some_list.remove(thing)
    
# 3) Filter it out
some_list = filter(lambda x: x != thing, some_list)

# 4) List comprehension 
some_list = [ x for x in some_list if x != thing ]