Folder zip Python
import shutil
shutil.make_archive(output_filename, 'zip', dir_name)
DigitalBorder
import shutil
shutil.make_archive(output_filename, 'zip', dir_name)languages = ['Java', 'Python', 'JavaScript']
versions = [14, 3, 6]
result = zip(languages, versions)
print(list(result))
# Output: [('Java', 14), ('Python', 3), ('JavaScript', 6)]
print(dict(result))
# Output: {'Java': 14, 'Python': 3, 'JavaScript': 6}namelist = ["Avish", "Piyush", "Tom"]
agelist = [17, 22, 38]
for name, age in zip(namelist, agelist):
print(name, age)
# Avish 17
# Piyush 22
# Tom 38>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> c = zip(a, b)
>>> print(c)
<zip object at 0x7f55cfca3080>
>>> list(c)
[(1, 4), (2, 5), (3, 6)]
>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> zipped = zip(x, y)
>>> list(zipped)
[(1, 4), (2, 5), (3, 6)]
>>> x2, y2 = zip(*zip(x, y))
>>> x == list(x2) and y == list(y2)
True