“Palindrome w skrypcie Shell” Kod odpowiedzi

Palindrome w skrypcie Shell

num=545
   
# Storing the remainder
s=0
   
# Store number in reverse 
# order
rev=""
   
# Store original number 
# in another variable
temp=$num
   
while [ $num -gt 0 ]
do
    # Get Remainder
    s=$(( $num % 10 ))  
      
    # Get next digit
    num=$(( $num / 10 )) 
      
    # Store previous number and
    # current digit in reverse 
    rev=$( echo ${rev}${s} ) 
done
   
if [ $temp -eq $rev ];
then
    echo "Number is palindrome"
else
    echo "Number is NOT palindrome"
fi