Jak połączyć wartość diff Colmun za pomocą grupy przez Postgres
SELECT movie, string_agg(actor, ', ') AS actor_list
FROM tbl
GROUP BY 1;
Fine Falcon
SELECT movie, string_agg(actor, ', ') AS actor_list
FROM tbl
GROUP BY 1;SELECT movie, string_agg(actor, ', ' ORDER BY actor) AS actor_list
FROM tbl
GROUP BY 1;