Wyświetlaj liczby od jednego do stu (w porządku rosnącym), ale liczba 2 nie powinna pojawiać się nigdzie w sekwencji. Na przykład liczby dwa ( 2) lub dwadzieścia trzy ( 23) nie powinny znajdować się w sekwencji.

Oto przykładowy wynik z nowymi liniami oddzielającymi liczby:

1
3
4
5
6
7
8
9
10
11
13
14
15
16
17
18
19
30
31
33
34
35
36
37
38
39
40
41
43
44
45
46
47
48
49
50
51
53
54
55
56
57
58
59
60
61
63
64
65
66
67
68
69
70
71
73
74
75
76
77
78
79
80
81
83
84
85
86
87
88
89
90
91
93
94
95
96
97
98
99
100

05AB1E , 6 bajtów

тLʒ2å_

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Wyjaśnienie

тL       # push [1 ... 100]
  ʒ      # filter, keep only elements that
   2å_   # does not contain 2

Taxi , 2399 2391 2370 1783 1773 1706 bajtów

-8 bajtów za uświadomienie sobie, że zamiast pozostawiać pewnego pasażera w Sunny Side Park na zawsze, bardziej warto zrzucić go z Riverview Bridge. Ach, jakie to piękne miasto.

-21 bajtów za wyciągnięcie komentarza, w który głupio zostawiłem.

-587 bajtów, po prostu zmieniając całą drogę, którą do tego podszedłem (najwyraźniej krótszą drogą jest arytmetyka; dzielenie liczb całkowitych [17, 27, 37, 47, ...] przez 9 daje sekwencję, ale musisz pominąć 20 sam.)

-17 bajtów, aby uświadomić sobie, że łańcuch zawierający cudzysłowy bez spacji nie potrzebuje przecież cudzysłowów (dzięki Jo King!).

-67 bajtów dla realizacji, że łamanie linii jest opcjonalne.

17 is waiting at Starchild Numerology.Go to Starchild Numerology:w 1 l 2 r 1 l 1 l 2 l.Pickup a passenger going to Cyclone.Go to Cyclone:e 1 l 2 r.[B]Pickup a passenger going to Cyclone.Pickup a passenger going to Divide and Conquer.9 is waiting at Starchild Numerology.Go to Starchild Numerology:s 2 l 2 r.Pickup a passenger going to Divide and Conquer.Go to Divide and Conquer:e 1 l 2 r 3 r 2 r 1 r.Pickup a passenger going to Trunkers.Go to Trunkers:e 1 r 3 r 1 l.Pickup a passenger going to The Babelfishery.Go to The Babelfishery:e 1 r 1 r.Pickup a passenger going to Post Office.\n is waiting at Writer's Depot.Go to Writer's Depot:n 5 l 2 l.Pickup a passenger going to Post Office.Go to Post Office:n 1 r 2 r 1 l.Go to Cyclone:s 1 r 1 l 2 r.Pickup a passenger going to Addition Alley.Pickup a passenger going to Equal's Corner.177 is waiting at Starchild Numerology.Go to Starchild Numerology:s 2 l 2 r.Pickup a passenger going to Equal's Corner.Go to Equal's Corner:w 1 l.Switch to plan C if no one is waiting.Pickup a passenger going to Sunny Skies Park.100 is waiting at Starchild Numerology.Switch to plan D.[C]10 is waiting at Starchild Numerology.[D]Go to Starchild Numerology:n 1 r.Pickup a passenger going to Addition Alley.Go to Sunny Skies Park:w 1 r.Go to Addition Alley:n 1 r 1 r 1 r.Pickup a passenger going to Cyclone.Go to Cyclone:n 1 l 1 l.Pickup a passenger going to Cyclone.Pickup a passenger going to Equal's Corner.917 is waiting at Starchild Numerology.Go to Starchild Numerology:s 2 l 2 r.Pickup a passenger going to Equal's Corner.Go to Equal's Corner:w 1 l.Switch to plan E if no one is waiting.Switch to plan F.[E]Go to Go More:n 1 l.Go to Cyclone:w 1 r.Switch to plan B.[F]

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Ten nie wygrywa w najbliższym czasie żadnych zawodów golfowych, ale postanowiłem wypróbować esolang Taxi.

Taxi to esolang, w którym całe programowanie odbywa się poprzez odbiór i wysadzenie pasażerów na różnych przystankach w fikcyjnym miasteczku Townsburg. Oczywiście w taksówce czasem zabraknie gazu, więc musisz także co jakiś czas odwiedzać stacje benzynowe i płacić za kredyty, które otrzymujesz jako opłatę (w tym przypadku muszę tylko zatrzymać się na benzynę - w Go More - raz na iterację w pętli!).

Użyłem kilku sztuczek, które nieco zmniejszają rozmiar pliku, takich jak przeformułowanie kierunków, takich east 1st left, 2nd rightjak e 1 l 2 r, usunięcie słowa thetam, gdzie jest opcjonalne, i użycie najmniej skomplikowanej trasy do wszystkich moich miejsc docelowych (niekoniecznie najkrótszej ścieżki).

Nienawidzę tego krótszego rozwiązania niż to, które pierwotnie wymyśliłem. To rozwiązanie tutaj jest bardziej ogólnym sposobem wykonania zadania, które można rozpocząć i zakończyć w dowolnym miejscu. Oto jest w całości.

2245 bajtów (znacznie bardziej ogólne)

1 is waiting at Starchild Numerology.Go to Starchild Numerology:w 1 l 2 r 1 l 1 l 2 l.Pickup a passenger going to Cyclone.Go to Cyclone:e 1 l 2 r.[B]Pickup a passenger going to Addition Alley.Pickup a passenger going to The Babelfishery.Go to The Babelfishery:n 2 r 2 r.Pickup a passenger going to Cyclone.Go to Cyclone:n 5 l 2 l.Pickup a passenger going to Chop Suey.Go to Zoom Zoom:n.0 is waiting at Writer's Depot.Go to Writer's Depot:w.Pickup a passenger going to Narrow Path Park.Go to Narrow Path Park:n 3 r 1 l 1 r.Go to Chop Suey:e 1 r 1 l 1 r.[C]Switch to plan E if no one is waiting.Pickup a passenger going to Crime Lab.2 is waiting at Writer's Depot.Go to Writer's Depot:n 1 l 3 l.Pickup a passenger going to Crime Lab.Go to Crime Lab:n 3 r 2 r.Switch to plan D if no one is waiting.Pickup a passenger going to KonKat's.Go to Narrow Path Park:n 5 l.Pickup a passenger going to KonKat's.Go to KonKat's:e 1 r.Pickup a passenger going to Narrow Path Park.Go to Narrow Path Park:n 2 l.Go to Chop Suey:e 1 r 1 l 1 r.Switch to plan C.[D]Go to Chop Suey:n 5 r 1 l.Switch to plan C.[E]Go to Narrow Path Park:n 1 l 1 r 1 l.Pickup a passenger going to Crime Lab.0 is waiting at Writer's Depot.Go to Writer's Depot:w 1 l 1 r 2 l.1 is waiting at Starchild Numerology.Pickup a passenger going to Crime Lab.Go to Crime Lab:n 3 r 2 r.Switch to plan F if no one is waiting.Pickup a passenger going to Riverview Bridge.Go to Cyclone:n 4 l 2 l.Pickup a passenger going to Post Office.Go to Riverview Bridge:n 2 r.\n is waiting at Writer's Depot.Go to Writer's Depot:w 2 l.Pickup a passenger going to Post Office.Go to Post Office:n 1 r 2 r 1 l.Go to Starchild Numerology:s 1 r 1 l 1 l 2 l.Switch to plan G.[F]Go to Cyclone:s 1 r 1 l 2 r.Pickup a passenger going to Riverview Bridge.Go to Riverview Bridge:n 2 r.Go to Starchild Numerology:w 2 l 3 l 2 r.[G]Pickup a passenger going to Addition Alley.Go to Addition Alley:e 1 l 2 r 3 r 1 r.Pickup a passenger going to Magic Eight.101 is waiting at Starchild Numerology.Go to Starchild Numerology:n 1 l 1 l 3 l 2 r.Pickup a passenger going to Magic Eight.Go to Magic Eight:w 1 r 2 r 1 r.Switch to plan H if no one is waiting.Pickup a passenger going to Cyclone.Go to Cyclone:n 1 l 2 r.Switch to plan B.[H]

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A jeśli dozwolone jest mega-oszukiwanie, ten jest znacznie krótszy niż którykolwiek z dwóch ostatnich.

456 bajtów (całkowite oszustwo)

1\n3\n4\n5\n6\n7\n8\n9\n10\n11\n13\n14\n15\n16\n17\n18\n19\n30\n31\n33\n34\n35\n36\n37\n38\n39\n40\n41\n43\n44\n45\n46\n47\n48\n49\n50\n51\n53\n54\n55\n56\n57\n58\n59\n60\n61\n63\n64\n65\n66\n67\n68\n69\n70\n71\n73\n74\n75\n76\n77\n78\n79\n80\n81\n83\n84\n85\n86\n87\n88\n89\n90\n91\n93\n94\n95\n96\n97\n98\n99\n100 is waiting at Writer's Depot.Go to Writer's Depot:w 1 l 2 r 1 l 2 l.Pickup a passenger going to Post Office.Go to Post Office:n 1 r 2 r 1 l.

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Python 2 , 39 bajtów

k=7
exec"k+=10;print(k>177)*10+k/9;"*81

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Używa operacji arytmetycznych tylko do generowania liczb bez 2.

Wartość kpodąża za postępem arytmetycznym 17, 27, 37, 47, ..., który po podzieleniu podłogi przez 9 daje 1,3,4,5,6,7,8,9,10,11,13,14,...liczby, które nie kończą się na 2. Aby pominąć 20 do 29, wyniki są zwiększane o 10 poza pewien próg.

JavaScript (ES6), 43 bajty

Zwraca sekwencję jako ciąg rozdzielany przecinkami.

f=(n=98)=>n?f(n-=n-27?n%10?1:2:11)+[,n+3]:1

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Po co to robić w ten sposób?

Możemy iterować od $1$ do $100$ i testować każdą liczbę /2/.test(n), co jest dość zwięzłym stwierdzeniem. Ale w tym scenariuszu musielibyśmy obsługiwać puste wpisy za pomocą czegoś podobnego (/2/.test(n)?'':...), co dodaje kilka dodatkowych bajtów.

Na przykład działałoby to dla 45 bajtów :

f=(n=1)=>n>99?n:(/2/.test(n)?'':[n,,])+f(n+1)

Lub działałoby to dla 44 bajtów , jeśli dopuszczalny jest przecinek wiodący:

f=(n=100)=>n?f(n-1)+(/2/.test(n)?'':[,n]):''

Podsumowując (i dopóki nie zostanie udowodnione inaczej) okazuje się, że krótsze jest od razu pominięcie wszystkich wartości $n$ które zawierają $2$ .

Skomentował

f =                 // f is a recursive function taking:
(n = 98) =>         // n = counter, initialized to 98
  n ?               // if n is not equal to 0:
    f(              //   prepend the result of a recursive call:
      n -=          //     update n:
        n - 27 ?    //       if n is not equal to 27:
          n % 10 ?  //         if n is not a multiple of 10:
            1       //           subtract 1 from n
          :         //         else:
            2       //           subtract 2 from n
        :           //       else (n = 27):
          11        //         subtract 11 from n (--> 16)
    ) +             //   end of recursive call
    [, n + 3]       //   append a comma, followed by n + 3; notice that this is the value
                    //   of n *after* it was updated for the recursive call; at the first
                    //   iteration, we have: n = 98 -> updated to 97 -> n + 3 = 100
  :                 // else (n = 0):
    1               //   output the first term '1' and stop recursion

R , 19 bajtów

grep(2,1:100,inv=T)

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Python 2 , 44 bajty

print[n for n in range(1,101)if'2'not in`n`]

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Perl 6 , 22 bajtów

put grep {!/2/},1..100

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Prawdopodobnie jest lepszy sposób na wykonanie bloku kodu, ale nie mogłem znaleźć przysłówka wyrażenia regularnego, aby odwrócić dopasowanie

PowerShell , 22 16 bajtów

1..100-notmatch2

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-6 bajtów dzięki mazzy

Generuje zakres 1do 100, a następnie wyciąga te obiekty, w których robią -notmatchliczbę 2. Uruchomienie -notmatchprzeciw tablicy w ten sposób działa jak filtr w tablicy. Każdy element jest pozostawiony w potoku, a dane wyjściowe są niejawne.

Haskell , 48 33 31 bajtów

Thanks @JonathanFrech for fifteen bytes saved, and @xnor for another two! I missed a big golf and didn't realize main=print$ can be omitted.

filter(all(/='2').show)[1..100]

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Easily extended by changing the 100. Stringifies all the numbers and keeps only those without a '2'.

Bash + GNU utilities, 16

• 1 byte saved thanks to @Dennis.

seq 100|sed /2/d

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Japt, 7 bytes

Lõs kø2

Lõs kø2     Full Program
Lõs         Range ["1"..."100"] (numbers are casted to string)
    k       Remove
     ø2     anything that contains "2"

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Java 10, 67 bytes

v->{for(int i=0;++i<101;)if(i%10!=2&i/10!=2)System.out.println(i);}

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Explanation:

v->{                           // Method with empty unused parameter and no return-type
  for(int i=0;++i<101;)        //  Loop `i` in the range (0, 101)
    if(i%10!=2                 //   If `i` modulo-10 is not 2
       &i/10!=2)               //   And `i` integer-divided by 10 is not 2 either
      System.out.println(i);}  //    Print `i` with a trailing newline

Retina, 19 17 bytes

100*
.
$.>`¶
A`2

Try it online! Edit: Saved 2 bytes thanks to @ovs, although the last line now includes a newline. Explanation:

100*

Insert 100 characters.

.
$.>`¶

Replace each character with the number of characters up to and including that character, plus a newline.

A`2

Remove all entries that contain a 2.

Stax, 6 bytes

Ç░τ╒╜h

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

AJ  10 squared
f   output each value in [1 .. n] satisfying the following filter
 E  get array of decimal digits in number
 2#     count the number of 2s
 !  logical not

Run this one

Wolfram Language (Mathematica), 42 bytes

Print@⌈Range[1,100,10/9]~Drop~{18,26}⌉

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The arithmetic sequence 1, 19/9, 29/9, 39/9, ... grows at just the right rate that taking the ceiling skips all the numbers ending in 2. Then we get rid of 20 through 29 by Dropping the values at indices 18 through 26.

C (GCC), 62 55 Bytes

• 7 Bytes thanks to Jonathan Frech

f(n){for(n=0;++n-101;n/10-2&&n%10-2&&printf("%d,",n));}

Loops from 1 to 100 and prints the number only if 2 is not in the ones or tens place.

Try it online!

Powershell, 19 bytes

1..100-split'.*2.*'

This script show null-value instead 'numbers with 2 inside' and completely solves the task 'number 2 shouldn’t appear anywhere in the sequence'.

Output:

1


3
4
5
6
7
8
9
10
11


13
14
15
16
17
18
19




















30
31


33
34
35
36
37
38
39
40
41


43
44
45
46
47
48
49
50
51


53
54
55
56
57
58
59
60
61


63
64
65
66
67
68
69
70
71


73
74
75
76
77
78
79
80
81


83
84
85
86
87
88
89
90
91


93
94
95
96
97
98
99
100

Powerhsell (output does not contain null-values), 24 bytes

1..100-split'.*2.*'-ne''

sh + coreutils, 16 chars

seq 100|sed /2/d

Generates sequence from 1 to 100 (inclusive) and deletes any lines that have '2' in them.

Z80Golf, 49 48 bytes

00000000: 1630 2e0a 5faf f57b fe02 2818 82ff f182  .0.._..{..(.....
00000010: ff92 3cf5 7dff f1bd 280a fe02 2803 f518  ..<.}...(...(...
00000020: e63c 18fa 7b3c bd20 db3e 31ff 3dff ff76  .<..{<. .>1.=..v

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Assembly:

ld d, 30h			; ascii '0' character
ld l, 0Ah			; number 10 and ascii newline
tens:
	ld e,a			; store tens digit
	xor a			; reset ones digit to 0
	push af			; store initial ones digit 0
	ones:
		ld a,e		; get stored tens digit
		cp 2
		jr z,cont	; if tens digit==2(e.g.20-29),skip loop
		add d
		rst 38h 	; print tens digit
		pop af		; get stored ones digit
		add d
		rst 38h 	; print ones digit
		sub d
		inc a		; increment ones digit
		push af		; store ones digit
		ld a, l
		rst 38h 	; print newline
		pop af		; get stored ones digit again
		cp l
		jr z,cont	; if ones digit==10, break loop
		cp 2
		jr z,inc_again	; if ones digit==2, incr again
		repeat_loop:
		push af		; store ones digit again
		jr ones		; repeat print loop
		inc_again:
			inc a
			jr repeat_loop
		
	cont:
	ld a,e			; get stored tens digit
	inc a			; increment tens digit
	cp l
	jr nz, tens		; if tens place!=10, continue loop
ld a,31h
rst 38h				; print '1'
dec a
rst 38h				; print '0'
rst 38h				; print '0'
halt

Saved one byte with the repeat_loop jump

Python 3, 53 51 50 49 46 bytes

['2'in str(n)or print(n)for n in range(1,101)]

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Not the strongest language for this task, but I'm new to golfing.

Thanks to the commenters for their tips!

Tcl, 44 bytes

time {if ![regexp 2 [incr i]] {puts $i}} 100

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time {if [incr i]%10!=2&$i/10!=2 {puts $i}} 100

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time {if {2 ni [split [incr i] ""]} {puts $i}} 100

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Kotlin, 32 bytes

{(1..100).filter{'2' !in ""+it}}

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Bash, 31 bytes

printf %d\\n {1..100}|grep -v 2

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Thanks to Digital Trauma for short loop.

ORK, 1092 bytes

There is such a thing as a t
A t can w a number
A t can d a number
A t has a t which is a number

When a t is to w a number:
I have a mathematician called M
M's first operand is the number
M's second operand is 1
M is to add
The number is M's result
My t is 0
I have a number called n
n is the number
I am to d n
M's first operand is my t
M's second operand is 1
M is to compare
I have a scribe called W
If M says it's less then W is to write the number
If M says it's less then W is to write " "
M's first operand is the number
M's second operand is 100
M is to compare
If M says it's less then I am to loop

When a t is to d a number:
I have a mathematician called M
M's first operand is the number
M's second operand is 10
M is to modulo
I have a mathematician called N
N's first operand is M's result
N's second operand is 2
N is to compare
If N says it's equal then my t is 1
M is to divide
The number is M's result
M's first operand is the number
M's second operand is 0
M is to compare
If M says it's greater then I am to loop

When this program starts:
I have a t called T
T is to w 0

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Objects R Kool. Output is a space-delimited list of numbers.

This translates (approximately) to the following pseudocode:

class t {
	int t;
	
	void w(number) {
		label T_W;
		mathematician M;
		M.first_operand = number;
		M.second_operand = 1;
		M.add();
		number = M.result;
		t = 0;
		int n = number;
		d(n);
		M.first_operand = t;
		M.second_operand = 1;
		M.compare();
		scribe W;
		if M.its_less { W.write(number); }
		if M.its_less { W.write(" "); }
		M.first_operand = number;
		M.second_operand = 100;
		M.compare();
		if M.its_less { goto T_W; }
	}
	
	void d(number) {
		label T_D;
		mathematician M;
		M.first_operand = number;
		M.second_operand = 10;
		M.modulo();
		mathematician N;
		N.first_operand = M.result;
		N.second_operand = 2;
		N.compare();
		if N.its_equal { t = 1; }
		M.divide();
		number = M.result;
		M.first_operand = number;
		M.second_operand = 0;
		M.compare();
		if M.its_greater { goto T_D; }
	}
}

void main() {
	t T;
	T.w(0);
}

As you can see, everything is done using objects, including basic math and IO functions (through the built-in mathematician and scribe classes). Only whole functions can loop, which explains the need for an object with two functions to do the work.

MathGolf, 7 6 bytes

♀╒Ç{2╧

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Explanation

♀╒       Push 100 and convert to 1-based range ([1,2,...,100])
  Č{     Inverse filter by block
    2╧   Does the number contain 2?

C (clang), 56 bytes

f(i){for(i=0;i++<100;i%10^2&&i/10^2&&printf("%d\n",i));}

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PHP 7.1, 40 bytes

while($i++<100)strstr($i,50)||print$i._;

prints numbers separated by underscores. Run with -nr or try it online.

Red, 44 bytes

repeat n 100[unless find form n"2"[print n]]

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Uses unless instead of if not, because why not? :)

brainfuck, 176 bytes

---------[[-<]-[>]>[>]-[-<]<++]-[>-<+++++++++]>--[>[->]<[<<<]>>[->]>-]<<,<-[-<]>[>]<[.[->+<]++++++++++.,<]>>[>]>>->-<<<<[>>>[<<[<]<.>>[>]>.[-<+>]++++++++++.,>]<<[<]<,<]>>>>.<..

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Shorter is definitely possible. This generates the numbers 1,3,4,5,6,7,8,9 and 0,1,3,4,5,6,7,8,9. First it outputs each number in the first list, then it outputs every combination of the first and second list, then finally prints just 100.

Explanation:

---------   Push minus 9
[           Repeat 9 times
  [-<]-[>]    Add the negative of the number to the first list
  >[>]-[-<]<  Add the negative of the number to the second list
  ++          Increment the counter
]
Tape: 255 254 253 252 251 250 249 248 247 0' 0 246 247 248 249 250 251 252 253 254
-[>-<+++++++++]>--  Push 197
Tape: 255 254 253 252 251 250 249 248 247 0 197' 246 247 248 249 250 251 252 253 254
[
  >[->]<    Subtract 197 from every element in both lists to convert to digits
  [<<<]>>
  [->]>-
]
Tape: 58 57 56 55 54 53 52 51 49 0' 49 50 51 52 53 54 55 56 57
<<,<-[-<]>[>]<  Remove the 0 and the 2 from the first list
Tape: 58 57 56 55 54 53 52 51 0 0 0' 49 50 51 52 53 54 55 56 57
[  Loop over the first list
  .[->+<]        Print digit
  ++++++++++.,<  Print a newline
]
>>[>]>>->-   Remove the 2 from the second list
<<<<      
[  Loop over first list
  >>>
  [  Loop over second list
    <<[<]<.        Print first digit
    >>[>]>.        Print second digit
    [-<+>]         Move second digit over one
    ++++++++++.,>  Print a newline
  ]
  <<[<]<,<  Remove the digit from the first list and move to the next
]
>>>>.<..  Print 100 using the second list

SimpleTemplate, 51 bytes

This was a fun challenge! And it is a challenge where my language can do well.

{@forfrom 1to100}{@if_ is notmatches"<2>"}{@echol_}

Cycles through all values from 1 to 100, outputting the ones that don't have 2, separated by a newline.

You can try it on http://sandbox.onlinephpfunctions.com/code/2c97a2b6954c29844f1079938da771d51e2e0d99

Ungolfed:

{@for i from 1 to 100}
    {@if i is not matches "<2>"}
        {@echo i, "\n"}
    {@/}
{@/}

The {@/} is used to close the {@for ...} and {@if ...}, but is optional.
When compiling to PHP, it adds the needed closing.

If you're curious, the golfed code results in this PHP code:

// {@forfrom 1to100}
// ~ optimization enabled ~ inlining the results
foreach(array(...) as $DATA['_']){

    // {@if_ is notmatches"<2>"}
    if(!(preg_match("<2>", (isset($DATA['_'])?$DATA['_']:null)))) {

        // {@echol_}
        echo implode('', $FN['array_flat']((isset($DATA['_'])?$DATA['_']:null)));echo PHP_EOL;


// AUTO-CLOSE
};};

Where $FN['array_flat'] is defined outside of this code.