Biorąc pod uwagę dwie liczby całkowite, wypisz dwie liczby całkowite, a następnie zakres między nimi (z wyłączeniem obu).

Kolejność zakresu musi być taka sama jak na wejściu.

Przykłady:

 Input        Output
 0,  5   ->   [0, 5, 1, 2, 3, 4]
-3,  8   ->   [-3, 8, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7]
 4,  4   ->   [4, 4]
 4,  5   ->   [4, 5]
 8,  2   ->   [8, 2, 7, 6, 5, 4, 3]
-2, -7   ->   [-2, -7, -3, -4, -5, -6]

R , 39 33 30 bajtów

c(a<-scan(),setdiff(a:a[2],a))

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Dzięki za zapisane bajty dla użytkownika 2390246 i J.Doe.

05AB1E , 4 bajty

Ÿ¦¨«

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Wyjaśnienie

    Ÿ      # inclusive range [a ... b]
     ¦¨    # remove the first and last element
       «   # append to input

Python 3 , 52 48 47 42 41 bajtów

lambda a,b:[a,b,*range(a,b,-(a>b)|1)[1:]]

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Połączone poprzednie wdrożenia.

Python 2 (Cython) , 36 35 bajtów

lambda x:x+range(*x,-cmp(*x)|1)[1:]

Dzięki @nwellnhof za grę w golfa na 1 bajcie!

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Python 2 , 37 bajtów

lambda x:x+range(*x+[-cmp(*x)|1])[1:]

Dzięki @JonasAusevicius za port do CPython!

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Perl 6 , 26 22 bajtów

{|@_,|[...^](@_).skip}

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Wyjaśnienie

{                    }
 |@_,   # Slip args a,b into result
      [...^](@_)  # Reduce args a,b with ...^ operator, same as a...^b
                .skip  # Skip first element
     |  # Slip into result

Python 2 , 40 bajtów

lambda x,y:[x,y]+range(x,y,-(y<x)|1)[1:]

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Python 3, 64 62 51 bytes

lambda a,b:[a,b]+[*range(a+1,b)]+[*range(a-1,b,-1)]

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Python 2, 58 45 bytes

lambda a,b:[a,b]+range(a+1,b)+range(a-1,b,-1)

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Japt, 8 bytes

cUr!õ kU

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             :Implicit input of array U
c            :Concatenate
 Ur          :  Reduce U by
   !õ        :   Inclusive range
      kU     :  Remove all elements in original U

JavaScript (ES6), 51 bytes

Takes input as (a)(b).

a=>g=(b,c=b)=>(b+=b<a|-(b>a))-a?[...g(b,c),b]:[a,c]

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Commented

a =>                // main function, taking a
  g = (             // g = recursive function
    b,              //     taking b
    c = b           // we save a backup of the original value of b into c
  ) =>              //
    (b +=           // add to b:
      b < a |       //   +1 if b is less than a
      -(b > a)      //   -1 if b is greater than a
    )               //   (or 0 if b = a)
    - a ?           // if the updated value of b is not equal to a:
      [             //   generate a new array:
        ...g(b, c), //     prepend all values generated by a recursive call
        b           //     append the current value of b
      ]             //
    :               // else:
      [a, c]        //   stop recursion and return the first 2 values: a and c

Python 2, 47 41 40 bytes

lambda a,b:[a,b]+range(a,b,a<b or-1)[1:]

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Here's mine, now that a lot of other Python answers have been posted

_{-6 bytes, thanks to G B}

Java 10, 109 108 104 102 93 62 bytes

Using a space-delimited String:

b->a->{var r=a+" "+b;for(;a<b?++a<b:--a>b;)r+=" "+a;return r;}

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Using a List:

b->a->{var r=new java.util.Stack();for(r.add(a),r.add(b);a<b?++a<b:--a>b;)r.add(a);return r;}

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(a<b?++a<b:--a>b can be ++a<b||(a-=2)>b for the same byte-count: Try it online for the String or Try it online for the List.)

Old (109 108 104 102 101 bytes) answer using an array:

a->b->{int s=a<b?1:-1,i=a!=b?(b-a)*s+1:2,r[]=new int[i];for(r[0]=a,r[1]=b;i>2;)r[--i]=b-=s;return r;}

-7 bytes thanks to @nwellnhof.

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Explanation:

a->b->{                // Method with 2 int parameters & int-array return-type
  int s=               //  Step integer, starting at:
        a<b?1          //   1 if the first input is smaller than the second
        :-1;           //   -1 otherwise
      i=               //  Array-index integer, starting at:
        a!=b?          //   If the inputs aren't equal:
         (b-a)*s+1     //    Set it to the absolute difference + 1
        :              //   Else:
         2,            //    Set it to 2
      r[]=new int[i];  //  Result-array of that size
  for(r[0]=a,          //  Fill the first value with the first input
      r[1]=b;          //  And the second value with the second input
      i>2;)            //  Loop `i` downwards in the range [`i`,2):
    r[--i]=            //   Decrease `i` by 1 first with `--i`
                       //   Set the `i`'th array-value to:
           b-=s;       //    If the step integer is 1: decrease `b` by 1
                       //    If the step integer is -1: increase `b` by 1
                       //    And set the array-value to this modified `b`
  return r;}           //  Return the result-array

APL (Dyalog Extended), 5 bytes

Anonymous infix function.

,,…~,

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, the first and last (lit. the concatenation of the arguments)

, and (lit. concatenated to)

… the range

~ without

, the first and last (lit. the concatenation of the arguments)

Haskell, 34 bytes

a#b=a:b:[a+1..b-1]++[a-1,a-2..b+1]

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Jelly, 4 bytes

,œ|r

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How it works

,œ|r  Main link. Left argument: a. Right argument: b

,     Pair; yield [a, b].
   r  Range; yield [a, ..., b].
 œ|   Perform multiset union.

J, 26 bytes

,,[|.@]^:(>{.)<.+1}.i.@|@-

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Explanation:

A dyadic verb (takes left and right argument)

                         -    subtracts the arguments
                       |@     and finds the absolute value
                    i.@       and makes a list 0..absolute difference
                 1}.          drops the fist element
                +             adds to the entire list
              <.              the smaller of the arguments
   |.@]                       reverses the list
       ^:                     only if
  [                           the left argument
         (>{.)                is greater than the first item of the list
 ,                            appends the list to
,                             the right argument appended to the left one

Octave, 45 bytes

@(a,b)[a b linspace(a,b,(t=abs(a-b))+1)(2:t)]

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J, 13 bytes

,,<.+i.@-~-.=

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     i.@-~       range [0 .. |difference|-1], reverse if the difference is positive
          -.=    remove the zero (either "=" is 0 or there’s nothing to remove)
  <.+            to each element add the smaller of the args
,,               prepend args

Batch, 107 bytes

@echo %1
@echo %2
@for %%s in (1 -1)do @for /l %%i in (%1,%%s,%2)do @if %1 neq %%i if %%i neq %2 echo %%i

Takes input as command-line arguments. Explanation:

@echo %1
@echo %2

Output the two integers.

@for %%s in (1 -1)do

Try both ascending and descending ranges.

@for /l %%i in (%1,%%s,%2)do

Loop over the inclusive range.

@if %1 neq %%i if %%i neq %2

Exclude the two integers.

echo %%i

Output the current value.

Pyth, 5 bytes

+QtrF

Input is a two-element list, [input 1, input 2]. Try it online here, or verify all the test cases at once here.

+QtrFQ   Implicit: Q=eval(input())
         Trailing Q inferred
   rFQ   Generate range [input 1 - input 2)
  t      Discard first element
+Q       Prepend Q

Red, 75 bytes

func[a b][s: sign? d: b - a prin[a b]loop absolute d - s[prin[""a: a + s]]]

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Clean, 49 bytes

import StdEnv
@a b=init[a,b:tl[a,a+sign(b-a)..b]]

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Ruby, 33 40 bytes

->a,b{[a,b]+[*a..b,*a.downto(b)][1..-2]}

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Temporary fix, trying to find a better idea

Python 2, 52 47 41 bytes

lambda i,j:[i,j]+range(i,j,(i<j)*2-1)[1:]

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-5 with thanks to @JoKing

-6 by slicing the first element from the range (idea stolen from and with credit to @TFeld)

Non-lambda version...

Python 2, 51 49 47 bytes

i,j=input();print[i,j]+range(i,j,(i<j)*2-1)[1:]

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-2 with thanks to @JoKing

APL (Dyalog Classic), 29 bytes

{⍺,⍵,(⌽⍣(⍺>⍵))(⍺⌊⍵)+¯1↓⍳|⍺-⍵}

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A port of my J solution

PHP (102 bytes)

function t($a,$b){count($r=range($a,$b))>1?array_splice($r,1,0,array_pop($r)):$r=[$a,$b];print_r($r);}

Sandbox

Unfortunately (for golf) PHP has rather verbose function names, which contribute a lot to the length. But the basic idea is to create a range, then pop off the last element and stitch it back in at offset 1. For the 4,4 example I had to add count($r=range($a,$b))>1?...:$r=[$a,$b]; which adds quite a bit, and unfortunately array_splice() is by reference which hit me for a few more bytes ($r= and a ;). All because of that "edge case", lol.

Well anyway enjoy!

Clojure, 61 bytes

(fn[[a b]](def s(if(> a b)-1 1))(list* a b(range(+ a s)b s)))

An anonymous function that takes a 2-vector as input and returns a list.

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Explanation

(fn [[a b]] ; An anonymous function that accepts a 2-vector as input, and destructures it to a and b
  (def s (if (> a b) -1 1)) ; If a > b assigns -1 to s and assigns 1 to s otherwise. This determines the order of the elements of the output list.
  (list* a b ; Creates a list with a and b as the first two elements. The remaining elements will be appended from the following range:
    (range (+ a s) b s))) ; A range starting at a+s and ending at b with step s

D, 85 bytes

T[]f(T)(T a,T b){T[]v=[a,b];T c=2*(b>a)-1;for(T i=a+c;a!=b&&b!=i;i+=c)v~=i;return v;}

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A port of @HatsuPointerKun's C++ answer into D.

TI-BASIC, 35 34 bytes

-1 byte from Misha Lavrov

Prompt A,B
Disp A,B
cos(π(A>B
For(I,A+Ans,B-Ans,Ans
Disp I
End

Charcoal, 15 bytes

ＩＥ²ＮＩ…⊕θηＩ⮌…⊕ηθ

Try it online! Link is to verbose version of code. Explanation:

ＩＥ²Ｎ

Print the inputs on separate lines.

Ｉ…⊕θη

Print the ascending range, if any.

Ｉ⮌…⊕ηθ

Print the reverse ascending reverse range, if any.

Dart, 85 84 bytes

f(a,b)=>[a,b]+((a-b).abs()>1?List.generate((a-b).abs()-1,(i)=>(a>b?-i-1:i+1)+a):[]);

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