Inicjalizacja tablicy wielowymiarowej w Javie

81

Jaki jest prawidłowy sposób zadeklarowania tablicy wielowymiarowej i przypisania do niej wartości?

Oto co mam:

int x = 5;
int y = 5;

String[][] myStringArray = new String [x][y];

myStringArray[0][x] = "a string";
myStringArray[0][y] = "another string";
spalony cukier
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Odpowiedzi:

64

Spróbuj zamienić odpowiednie wiersze na:

myStringArray[0][x-1] = "a string";
myStringArray[0][y-1] = "another string";

Twój kod jest niepoprawny, ponieważ tablice podrzędne mają długość y, a indeksowanie zaczyna się od 0. Tak więc ustawienie myStringArray[0][y]lub myStringArray[0][x]nie powiedzie się, ponieważ indeksy xi ysą poza zakresem.

String[][] myStringArray = new String [x][y];jest prawidłowym sposobem inicjalizacji prostokątnej tablicy wielowymiarowej. Jeśli chcesz, aby była postrzępiona (każda podtablica ma potencjalnie inną długość), możesz użyć kodu podobnego do tej odpowiedzi . Zauważ jednak, że twierdzenie Johna, że ​​musisz ręcznie tworzyć tablice podrzędne, jest niepoprawne w przypadku, gdy chcesz uzyskać idealnie prostokątną tablicę wielowymiarową.

jameshales
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105

Java nie ma „prawdziwych” wielowymiarowych tablic.

Na przykład arr[i][j][k]jest równoważne z ((arr[i])[j])[k]. Innymi słowy, arrjest po prostu tablicą, tablicami, tablicami .

Więc jeśli wiesz, jak działają tablice, wiesz, jak działają tablice wielowymiarowe!


Deklaracja:

int[][][] threeDimArr = new int[4][5][6];

or, with initialization:

int[][][] threeDimArr = { { { 1, 2 }, { 3, 4 } }, { { 5, 6 }, { 7, 8 } } };

Access:

int x = threeDimArr[1][0][1];

or

int[][] row = threeDimArr[1];

String representation:

Arrays.deepToString(threeDimArr);

yields

"[[[1, 2], [3, 4]], [[5, 6], [7, 8]]]"

Useful articles

aioobe
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3
How is that not a "true" multidimensional array?
dhardy
13
With "true" multidimensional arrays I refer to "non-jagged" arrays. For the difference between jagged arrays and "true" multidimensional arrays, see this question.
aioobe
2
An int[i][j][k] has length i, so really it's equivalent to an ((int[k])[j])[i]. The sizes in the declaration are written backwards with respect to the types, I suppose to make multidimensional arrays more closely resemble matrices in mathematics.
Milosz
Thanks for mentioning Arrays.deepToString.
samir105
60

You can also use the following construct:

String[][] myStringArray = new String [][] { { "X0", "Y0"},
                                             { "X1", "Y1"},
                                             { "X2", "Y2"},
                                             { "X3", "Y3"},
                                             { "X4", "Y4"} };
A_M
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13

You can declare multi dimensional arrays like :

// 4 x 5 String arrays, all Strings are null
// [0] -> [null,null,null,null,null]
// [1] -> [null,null,null,null,null]
// [2] -> [null,null,null,null,null]
// [3] -> [null,null,null,null,null]

String[][] sa1 = new String[4][5];
for(int i = 0; i < sa1.length; i++) {           // sa1.length == 4
    for (int j = 0; j < sa1[i].length; j++) {     //sa1[i].length == 5
        sa1[i][j] = "new String value";
    }
}


// 5 x 0  All String arrays are null
// [null]
// [null]
// [null]
// [null]
// [null]
String[][] sa2 = new String[5][];
for(int i = 0; i < sa2.length; i++) {
    String[] anon = new String[ /* your number here */];
    // or String[] anon = new String[]{"I'm", "a", "new", "array"};
    sa2[i] = anon;
}

// [0] -> ["I'm","in","the", "0th", "array"]
// [1] -> ["I'm", "in", "another"]
String[][] sa3 = new String[][]{ {"I'm","in","the", "0th", "array"},{"I'm", "in", "another"}};
Clint
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9

Multidimensional Array in Java

Returning a multidimensional array

Java does not truely support multidimensional arrays. In Java, a two-dimensional array is simply an array of arrays, a three-dimensional array is an array of arrays of arrays, a four-dimensional array is an array of arrays of arrays of arrays, and so on...

We can define a two-dimensional array as:

  1. int[ ] num[ ] = {{1,2}, {1,2}, {1,2}, {1,2}}

  2. int[ ][ ] num = new int[4][2]

    num[0][0] = 1;
    num[0][1] = 2;
    num[1][0] = 1;
    num[1][1] = 2;
    num[2][0] = 1;
    num[2][1] = 2;
    num[3][0] = 1;
    num[3][1] = 2;
    

    If you don't allocate, let's say num[2][1], it is not initialized and then it is automatically allocated 0, that is, automatically num[2][1] = 0;

  3. Below, num1.length gives you rows.

  4. While num1[0].length gives you the number of elements related to num1[0]. Here num1[0] has related arrays num1[0][0] and num[0][1] only.

  5. Here we used a for loop which helps us to calculate num1[i].length. Here i is incremented through a loop.

    class array
    {
        static int[][] add(int[][] num1,int[][] num2)
        {
            int[][] temp = new int[num1.length][num1[0].length];
            for(int i = 0; i<temp.length; i++)
            {
                for(int j = 0; j<temp[i].length; j++)
                {
                    temp[i][j] = num1[i][j]+num2[i][j];
                }
            }
            return temp;
        }
    
        public static void main(String args[])
        {
            /* We can define a two-dimensional array as
                 1.  int[] num[] = {{1,2},{1,2},{1,2},{1,2}}
                 2.  int[][] num = new int[4][2]
                     num[0][0] = 1;
                     num[0][1] = 2;
                     num[1][0] = 1;
                     num[1][1] = 2;
                     num[2][0] = 1;
                     num[2][1] = 2;
                     num[3][0] = 1;
                     num[3][1] = 2;
    
                     If you don't allocate let's say num[2][1] is
                     not initialized, and then it is automatically
                     allocated 0, that is, automatically num[2][1] = 0;
                  3. Below num1.length gives you rows
                  4. While num1[0].length gives you number of elements
                     related to num1[0]. Here num1[0] has related arrays
                     num1[0][0] and num[0][1] only.
                  5. Here we used a 'for' loop which helps us to calculate
                     num1[i].length, and here i is incremented through a loop.
            */
            int num1[][] = {{1,2},{1,2},{1,2},{1,2}};
            int num2[][] = {{1,2},{1,2},{1,2},{1,2}};
    
            int num3[][] = add(num1,num2);
            for(int i = 0; i<num1.length; i++)
            {
                for(int j = 0; j<num1[j].length; j++)
                    System.out.println("num3[" + i + "][" + j + "]=" + num3[i][j]);
            }
        }
    }
    
Isabella Engineer
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4

I'll add that if you want to read the dimensions, you can do this:

int[][][] a = new int[4][3][2];

System.out.println(a.length);  // 4
System.out.println(a[0].length); // 3
System.out.println(a[0][0].length); //2

You can also have jagged arrays, where different rows have different lengths, so a[0].length != a[1].length.

Vlad
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1
 int[][] myNums = { {1, 2, 3, 4, 5, 6, 7}, {5, 6, 7, 8, 9, 10, 11} };
 for (int x = 0; x < myNums.length; ++x) {
    for(int y = 0; y < myNums[i].length; ++y) {
       System.out.print(myNums[x][y]);
    }
 }

Output

1 2 3 4 5 6 7 5 6 7 8 9 10 11

Fridjato Part Fridjat
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-3

You can look at this to start off:

    int [][][] i = {                //third dimension curly brace
                     {               // second dimension curly brace
                        {            //first dimension curly brace
                           1,1,1    //elements
                        },           
                    {3,3,3},    
                    {2,2,2}     
                      },
                      {
                         {
                          1,1,1
                         },
                         {3,3,3},
                         {2,2,2}
                       }
                    };      
Ranjit
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2
Is this an answer or what?
maytham-ɯɐɥʇʎɐɯ
7
Then I hope he is hungry to eat it
maytham-ɯɐɥʇʎɐɯ