“Python Regex subn re.subn ()” Kod odpowiedzi

Python Regex subn re.subn ()

import re

print(re.subn('ub', '~*', 'Subject has Uber booked already'))

t = re.subn('ub', '~*', 'Subject has Uber booked already',
			flags=re.IGNORECASE)
print(t)
print(len(t))

# This will give same output as sub() would have
print(t[0])