Python Boto3 ypload_file do S3
s3.meta.client.upload_file(Filename=filename_and_full_path, Bucket=my_bucket, Key=prefix_key_plus_filename_only)
Impossible Impala
s3.meta.client.upload_file(Filename=filename_and_full_path, Bucket=my_bucket, Key=prefix_key_plus_filename_only)