“Link Markdown PHP Regex” Kod odpowiedzi

Link Markdown PHP Regex

$text = 'Link to [Google](https://www.google.com/)';
echo preg_replace('/\[(.*?)\]\s*\(((?:http:\/\/|https:\/\/)(?:.+))\)/', '<a href="$2">$1</a>', $text);
// Outputs: Link to <a href="https://www.google.com/">Google</a>