pętla pandy przez rzędy
for index, row in df.iterrows():
print(row['c1'], row['c2'])
Output:
10 100
11 110
12 120
Real Ratel
for index, row in df.iterrows():
print(row['c1'], row['c2'])
Output:
10 100
11 110
12 120df = pd.DataFrame([{'c1':10, 'c2':100}, {'c1':11,'c2':110}, {'c1':12,'c2':120}])
for index, row in df.iterrows():
print(row['c1'], row['c2'])# Option 1
for row in df.iterrows():
print row.loc[0,'A']
print row.A
print row.index()
# Option 2
for i in range(len(df)) :
print(df.iloc[i, 0], df.iloc[i, 2]) import pandas as pd
df = pd.DataFrame({'c1': [10, 11, 12], 'c2': [100, 110, 120]})
df = df.reset_index() # make sure indexes pair with number of rows
for index, row in df.iterrows():
print(row['c1'], row['c2'])import pandas as pd
import numpy as np
df = pd.DataFrame({'c1': [10, 11, 12], 'c2': [100, 110, 120]})
for index, row in df.iterrows():
print(row['c1'], row['c2'])
# creating a list of dataframe columns
columns = list(df)
for i in columns:
# printing the third element of the column
print (df[i][2])